Journal Archive

/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root
 * @return {number[]}
 */
var preorderTraversal = function(root, preorder = []) {
    if (!root) return preorder;
    preorder.push(root.val);
    if (root.left) {
        preorderTraversal(root.left, preorder);
    }
    if (root.right) {
        preorderTraversal(root.right, preorder);
    }
    return preorder;
};

Day 66: Solving one of LeetCode problems

144. Binary Tree Preorder Traversal Difficulty - Easy

Given the root of a binary tree, return the preorder traversal of its nodes' values.

 

Example 1:

Input: root = [1,null,2,3]
Output: [1,2,3]
		

Example 2:

Input: root = []
Output: []
		

Example 3:

Input: root = [1]
Output: [1]
		

 

Follow up: Recursive solution is trivial, could you do it iteratively?