Journal Archive

/**
 * @param {number} x
 * @param {number} n
 * @return {number}
 */
var myPow = function(x, n) {
    if (n === 0) return 1;
    if (n === 1) return x;
    let minus = n < 0;
    let power = Math.abs(n);
    let ans = power % 2 === 0 ? myPow(x * x, power / 2) : myPow(x * x, (power - 1) / 2) * x;
    
    return minus ? 1 / ans: ans;
};

Day 86: Solving one of LeetCode problems

50. Pow(x, n) Difficulty - Medium

Implement pow(x, n), which calculates x raised to the power n (i.e., xn).

 

Example 1:

Input: x = 2.00000, n = 10
Output: 1024.00000
		

Example 2:

Input: x = 2.10000, n = 3
Output: 9.26100
		

Example 3:

Input: x = 2.00000, n = -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25