Journal Archive

/* Write your PL/SQL query statement below */
SELECT DISTINCT author_id AS id
FROM Views
WHERE author_id = viewer_id
ORDER BY id ASC;

Day 98: Solving one of LeetCode problems

1148. Article Views I Difficulty - Easy

Table: Views

+---------------+---------+
    | Column Name   | Type    |
    +---------------+---------+
    | article_id    | int     |
    | author_id     | int     |
    | viewer_id     | int     |
    | view_date     | date    |
    +---------------+---------+
    There is no primary key for this table, it may have duplicate rows.
    Each row of this table indicates that some viewer viewed an article (written by some author) on some date. 
    Note that equal author_id and viewer_id indicate the same person.
    

 

Write an SQL query to find all the authors that viewed at least one of their own articles.

Return the result table sorted by id in ascending order.

The query result format is in the following example.

 

Example 1:

Input: 
    Views table:
    +------------+-----------+-----------+------------+
    | article_id | author_id | viewer_id | view_date  |
    +------------+-----------+-----------+------------+
    | 1          | 3         | 5         | 2019-08-01 |
    | 1          | 3         | 6         | 2019-08-02 |
    | 2          | 7         | 7         | 2019-08-01 |
    | 2          | 7         | 6         | 2019-08-02 |
    | 4          | 7         | 1         | 2019-07-22 |
    | 3          | 4         | 4         | 2019-07-21 |
    | 3          | 4         | 4         | 2019-07-21 |
    +------------+-----------+-----------+------------+
    Output: 
    +------+
    | id   |
    +------+
    | 4    |
    | 7    |
    +------+