Journal Archive

/**
 * @param {number[][]} matrix
 * @return {void} Do not return anything, modify matrix in-place instead.
 */
var rotate = function(matrix) {
    const n = matrix.length;
    // horizontal swap
    for (let r = 0; r < n; r++) {
        for (let c = 0; c < Math.floor(n / 2); c++) {
            [matrix[r][c], matrix[r][n - c - 1]] = [matrix[r][n - c - 1], matrix[r][c]]
        }
    }
    
    // diagonal swap
    for (let r = 0; r < n; r++) {
        for (let c = n - 1 - r, step = 0; c >= 0; c--, step++) {
            [matrix[r][c], matrix[r + step][c + step]] = [matrix[r + step][c + step], matrix[r][c]]
        }
    }
    
};

Day 85: Solving one of LeetCode problems

48. Rotate Image Difficulty - Medium

You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).

You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.

 

Example 1:

Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]
		

Example 2:

Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]